(x+2)^2+x(x-3)=1

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Solution for (x+2)^2+x(x-3)=1 equation: 



(x+2)^2+x(x-3)=1

We move all terms to the left:

(x+2)^2+x(x-3)-(1)=0

We multiply parentheses

x^2+(x+2)^2-3x-1=0

We add all the numbers together, and all the variables

x^2-3x+(x+2)^2-1=0

We move all terms containing x to the left, all other terms to the right

x^2-3x+(x+2)^2=1

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